# 2. Regression¶

Regression is supervised learning with continuous (or sometimes discrete) labels. You are given labeled data consisting of features and labels $$\{\vec{x}_i, y_i\}$$. The goal is to find a function that describes their relationship, $$\hat{f}(\vec{x}) = \hat{y}$$. This lecture introduces some probability theory, especially expectations. You can get a refresher of probability of random variables and/or expections. We also use and discuss linear regression techniques. A more formal discussion of the concepts discussed here can be found in Chapter 3 of Bishop’s Pattern Recognition and Machine Learning[Bis06].

## 2.1. Running This Notebook¶

Click the    above to launch this page as an interactive Google Colab. See details below on installing packages, either on your own environment or on Google Colab

As usual, the code below sets-up our imports.

import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
import matplotlib as mpl
import numpy as np
import jax.numpy as jnp
import jax.experimental.optimizers as optimizers
import jax
import warnings
warnings.filterwarnings('ignore')
sns.set_context('notebook')
sns.set_style('dark',  {'xtick.bottom':True, 'ytick.left':True, 'xtick.color': '#666666', 'ytick.color': '#666666',
'axes.edgecolor': '#666666', 'axes.linewidth':     0.8 , 'figure.dpi': 300})
color_cycle = ['#1BBC9B', '#F06060', '#5C4B51', '#F3B562', '#6e5687']
mpl.rcParams['axes.prop_cycle'] = mpl.cycler(color=color_cycle)
features_start_at = list(soldata.columns).index('MolWt')
feature_names = soldata.columns[features_start_at:]
np.random.seed(0)


## 2.2. Overfitting¶

We’ll be working again with the AqSolDB[SKE19] dataset. It has about 10,000 unique compounds with measured solubility in water (label) and 17 molecular descriptors (features). we need to create a better assessment of our supervised ML models. The goal of our ML model is to predict solubility of new unseen molecules. Therefore, to assess we should test on unseen molecules. We will split our data into two: training data and testing data. Typically this is done with an 80%/20%, so that you train on 80% of your data. In our case, we’ll just do 50%/50% because we have plenty of data. We’ll be using a subset, 50 molecules chosen randomly, rather than the whole dataset. So we’ll have 50 training molecules and 50 testing molecules.

Let’s begin by seeing what effect the split of train/data has on our linear model introduced in the previous chapter.

# standardize the features
soldata[feature_names] -= soldata[feature_names].mean()
soldata[feature_names] /= soldata[feature_names].std()

# Get 50 points and split into train/test
sample = soldata.sample(50, replace=False)
train = sample[:25]
test = sample[25:]

# convert from pandas dataframe to numpy arrays
x = train[feature_names].values
y = train['Solubility'].values
test_x = test[feature_names].values
test_y = test['Solubility'].values


We will again use a linear model, $$\hat{y} = \vec{w}\vec{x} + b$$. One change we’ll make is using the jit decorator from jax. This decorator will tell jax to inspect our function, simplify it, and compile it to run quickly on a GPU (if available) or CPU. The rest of our work is the same as the previous chapter. We begin with defining our loss, which is mean squared error (MSE) again.

# define our loss function
@jax.jit
def loss(w, b, x, y):
return jnp.mean((y - jnp.dot(x, w) - b)**2)
w = np.random.normal(size=x.shape[1])
b = 0.

WARNING:absl:No GPU/TPU found, falling back to CPU. (Set TF_CPP_MIN_LOG_LEVEL=0 and rerun for more info.)

(DeviceArray([-1.5061271 ,  1.1999842 , -1.2835604 , -1.6213734 ,
-2.381636  , -1.1584275 , -2.3219411 , -1.6100702 ,
-1.92757   ,  2.2736402 , -2.8762534 , -3.8425767 ,
-0.6540491 , -2.5890539 , -1.6287824 , -0.02244286,
-0.8838823 ], dtype=float32),
DeviceArray(6.237296, dtype=float32))


Now we will train our model, again using gradient descent. This time we will not batch, since our training data only has 25 points. Can you see what the learning rate is? Why is it so different from the last chapter when we used the whole dataset?

loss_progress = []
test_loss_progress = []
eta = 0.05
for i in range(2000):
w -= eta * grad[0]
b -= eta * grad[1]
loss_progress.append(loss(w, b, x, y))
test_loss_progress.append(loss(w, b, test_x, test_y))
plt.plot(loss_progress, label='Training Loss')
plt.plot(test_loss_progress, label='Testing Loss')

plt.xlabel('Step')
plt.yscale('log')
plt.legend()
plt.ylabel('Loss')
plt.show()

yhat = x @ w + b
plt.plot(y, y, ':', linewidth=0.2)
plt.plot(y, x @ w + b, 'o')
plt.xlim(min(y), max(y))
plt.ylim(min(y), max(y))
plt.text(min(y) + 1, max(y) - 2, f'correlation = {np.corrcoef(y, yhat)[0,1]:.3f}')
plt.text(min(y) + 1, max(y) - 3, f'loss = {np.sqrt(np.mean((y - yhat)**2)):.3f}')
plt.title('Training Data')
plt.show()

yhat = test_x @ w + b
plt.plot(test_y, test_y, ':', linewidth=0.2)
plt.plot(test_y, yhat, 'o')
plt.xlim(min(test_y), max(test_y))
plt.ylim(min(test_y), max(test_y))
plt.text(min(test_y) + 1, max(test_y) - 2, f'correlation = {np.corrcoef(test_y, yhat)[0,1]:.3f}')
plt.text(min(test_y) + 1, max(test_y) - 3, f'loss = {np.sqrt(np.mean((test_y - yhat)**2)):.3f}')
plt.title('Testing Data')
plt.show()


We’ve plotted above the loss on our training data and testing data. The loss on training goes down after each step, as we would expect for gradient descent. However, the testing loss goes down and then starts to go back up. This is called overfitting. This is one of the key challenges in ML and we’ll often be discussing it.

Overfitting is a result of training for too many steps or with too many parameters, resulting in our model learning the noise in the training data. The noise is specific for the training data and when computing loss on the test data there is poor performance.

To understand this, let’s first define noise. Assume that there is a “perfect” function $$f(\vec{x})$$ that can compute labels from features. Our model is an estimate $$\hat{f}(\vec{x})$$ of that function. Even $$f(\vec{x})$$ will not reproduce the data exactly becuase our features do not capture everything that goes into solubility and/or there is error in the solbulity measurements themsevles. Mathematically,

(2.1)$$$y = f(\vec{x}) + \epsilon$$$

where $$\epsilon$$ is a random number with mean 0 and unknown standard deviation $$\sigma$$. $$\epsilon$$ is the noise. When fitting our function, $$\hat{f}(\vec{x})$$ the noise is fixed because our labels $$y$$ are fixed. That means we can accidentally learn approximate the sum of $$f(\vec{x})$$ and the noise $${\epsilon_i}$$ instead of only capturing $$f(\vec{x})$$. The noise is random and uncorrelated with solubility. When we move to our testing dataset, this noise changes because we have new data and our model’s effort to reproduce noise is useless because the new data has new noise. This leads to worse performance.

Overfitting arises when three things happen: you have noise, you have extra features or some part of your features are not correlated with the labels, and your training has converged (your model fit is at the global minimum). This last one is what we saw above. Our model wasn’t overfit after about 100 steps (the training and testing loss were both decreasing), but then they starting going in opposite directions. Let’s see how these things interplay to lead to overfitting in an example where we can exactly control the features and noise.

### 2.2.1. Overfitting with Synthetic Data¶

We’ll explore overfitting in a synthetic example. Our real function we’re trying to learn will be:

(2.2)$$$f(x) = x^3 - x^2 + x - 1$$$

which we can rewrite as a linear model:

(2.3)$$$f(\vec{x}) = \vec{w}\cdot\vec{x} = [1, -1, 1, -1]\cdot[x^3, x^2, x, 1]$$$

where our features are $$[x^3, x^2, x, 1]$$. To do our split, we’ll take the positive points as training data and the negative as testing data. To avoid the issue of convergence, we will use least squares to fit these models instead of gradient descent.

Let’s establish a benchmark. How well can a model do without noise? We’ll use 10 training data points and 10 testing data points. We’ll put our testing data in the center of the polynomial.

Expand the python cells below to see how this is implemented.

# generate data from polynomial
N = 20
syn_x = np.linspace(-3, 3, N)
# create feature matrix
syn_features = np.vstack([syn_x**3, syn_x**2, syn_x, np.ones_like(syn_x)]).T
syn_labels = syn_x **3 - syn_x**2 + syn_x - 1

# split data into train/test
indices = list(range(0, N // 4)) + list(range(3 * N // 4, N))
test_indices = list(range(N // 4, 3 * N // 4))
train_x = syn_features[indices]
train_y = syn_labels[indices]
test_x = syn_features[test_indices]
test_y = syn_labels[test_indices]

# fit using numpy least squares method.
w, *_ = np.linalg.lstsq(train_x, train_y)

# plotting code
plt.plot(syn_x[indices], train_y, 'o', label='Training labels')
plt.plot(syn_x[test_indices], test_y, 'o', label='Testing labels')
plt.ylim(-40, 40)
plt.plot(syn_x, jnp.dot(syn_features, w), label='Fit Model')
plt.plot(syn_x, syn_labels, '--', label='Ground Truth')
plt.text(0, -20, f'Training Loss {loss(w,0,train_x, train_y):.2f}')
plt.text(0, -30, f'Testing Loss {loss(w,0, test_x, test_y):.2f}')
plt.legend()
plt.title('No Noise, Perfect Features')
plt.show()


There is no overfitting and the regssion is quite accurate without noise. Now we’ll add noise to both the training labels.

train_y = train_y + np.random.normal(scale=5, size=train_y.shape)

w, *_ = np.linalg.lstsq(train_x, train_y)
plt.plot(syn_x[indices], train_y, 'o', label='Training labels')
plt.plot(syn_x[test_indices], test_y, 'o', label='Testing labels')
plt.ylim(-40, 40)
plt.plot(syn_x, jnp.dot(syn_features, w), label='Fit Model')
plt.plot(syn_x, syn_labels, '--', label='Ground Truth')
plt.text(0, -20, f'Training Loss {loss(w,0,train_x, train_y):.2f}')
plt.text(0, -30, f'Testing Loss {loss(w,0, test_x, test_y):.2f}')
plt.legend()
plt.title('Noise, Perfect Features')
plt.show()


Adding noise reduces the accuracy on the training data. The testing labels have no noise and the model is not overfit, so the accuracy is good for the testing loss.

Now we’ll try adding redundant features. Our new features will be $$[x^6, x^5, x^4, x^3, x^2, x, 1]$$. Still less than our data point number but not all features are necessary to fit the labels.

syn_features = np.vstack([syn_x**i for i in range(7)]).T

train_x = syn_features[indices]
test_x = syn_features[test_indices]
test_y = syn_labels[test_indices]

w, *_ = np.linalg.lstsq(train_x, train_y)
plt.plot(syn_x[indices], train_y, 'o', label='Training labels')
plt.plot(syn_x[test_indices], test_y, 'o', label='Testing labels')
plt.ylim(-40, 40)
plt.plot(syn_x, jnp.dot(syn_features, w), label='Fit Model')
plt.plot(syn_x, syn_labels, '--', label='Ground Truth')
plt.text(0, -20, f'Training Loss {loss(w,0,train_x, train_y):.2f}')
plt.text(0, -30, f'Testing Loss {loss(w,0, test_x, test_y):.2f}')
plt.legend(loc='upper left')
plt.title('Noise, Extra Features')
plt.show()


This is an overfit model. The training loss went down (note the noise was the same in the previous two examples), but at the expense of a large decrease in testing loss. This wasn’t possible in the previous example because over-fitting to noise wasn’t feasible when each feature was necessary to capture the correlation with the labels.

Let’s see an example where the feature number is the same but they aren’t perfectly correlated with labels, meaning we cannot match the labels even if there was no noise.

syn_features = np.vstack([syn_x**2, syn_x, np.exp(-syn_x**2), np.cos(syn_x), np.ones_like(syn_x)]).T

train_x = syn_features[indices]
test_x = syn_features[test_indices]

w, *_ = np.linalg.lstsq(train_x, train_y)
plt.plot(syn_x[indices], train_y, 'o', label='Training labels')
plt.plot(syn_x[test_indices], test_y, 'o', label='Testing labels')
plt.ylim(-40, 40)
plt.plot(syn_x, jnp.dot(syn_features, w), label='Fit Model')
plt.plot(syn_x, syn_labels, '--', label='Ground Truth')
plt.text(0, -20, f'Training Loss {loss(w,0,train_x, train_y):.2f}')
plt.text(0, -30, f'Testing Loss {loss(w,0, test_x, test_y):.2f}')
plt.legend(loc='upper left')
plt.title('Noise, Imperfectly Correlated Features')
plt.show()


It’s arguable if this is overfitting. Yes, the testing loss is high but it could be argued it’s more to do with the poor feature choice. In any case, even though our parameter number is less than the clear cut case above, there is still left over variance in our features which can be devoted to fitting noise.

Would there overfitting with fewer features that are perfectly correlated with labels?

### 2.2.2. Overfitting Conclusion¶

• Overfitting is inevitable in real data because we cannot avoid noise and rarely have the perfect features.

• Overfitting can be assessed by splitting our data into a train and test split, which mimics how we would use the model (i.e., on unseen data).

• Overfitting is especially affected by having too many features or features that don’t correlate well with the labels.

• We can identify overfitting from a loss curve which shows the testing loss rising while training loss is decreasing.

## 2.3. Exploring Effect of Feature Number¶

We’ve seen that overfitting is sensitive to the number and choice of features. Feature selection is a critical decision in supervised learning. We’ll return the solubility dataset to discuss this. It has 17 molecular descriptors, but these are just a small fraction of the possible molecular descriptors that can be used. For example, there is a software called Dragon that can compute over 5,000 descriptors. You can also create linear combinations of descriptors and pass them through functions. Then there is the possibility of experimental data, data from molecular simulations, and from quantum caclulations. There is essentially an unlimited number of possible molecular descriptors. We’ll start this chapter by exploring what effect the feature number has on the data.

We are now working with a real dataset, which means there is randomness from which features we choose, which training data we choose, and randonmness in the lables themsevles. In the results below, they are averaged over possible features and possible training data splits to deal with this. Thus the code is complex. You can see it on the Github repository, but I’ve omitted it for simplicity.

Fig. 2.1 Effect of feature number on 25 training data points averaged over 10 data samples/feature choices combinations.

Fig. 2.1 shows the effect of choosing different features on both the loss on training data and the loss on test data. There are three regimes in this plot. At 1-3 features, we are underfit meaning both the training and testing losses could be improved with more features or more training. In this case, it is because there are too few features. Until about 10 features, we see that adding new features slightly improves training data but doesn’t help test data meaning we’re probably slightly overfitting. Then at 10, there is a large increase as we move to the overfit regime. Finally at about 30 features, our model is no longer converging and training loss rises because it is too difficult to train the increasingly compelx model. “Difficult” here is a relative term; you can easily train for more time on this simple model but this is meant as an example.

Fig. 2.2 Effect of feature number on 250 training data points averaged over 10 data samples/feature choices combinations.

Fig. 2.2 shows the same analysis but for 250 train and 250 test data. The accuracy on test data is better (about 1.9 vs 2.5). There is not much overfitting visible here. The model is clearly underfit until about 10 features and then each additional feature has little effect. Past 20 features, we again see an underfit because the model is not trained well. This could fixed by adding more training steps.

Increasing feature numbers is useful up to a certain point. Although some methods are unstable when the number of features is exactly the same as the number of data points, there is reason overfitting begins at or near feature numbers equal to the number of data points. Overfitting can disappear at large feature numbers because of model size and complexity. Here there is also a risk of underfitting.

The risk of overfitting is lower as your dataset size increases. The reason for this is that the noise becomes smaller than the effect of labels on training as you increase data points. Recall from the Central Limit Theorem that reducing noise by a factor of 10 requires 100 more times data, so this is not as efficient as choosing better features. Thinking about these trade-offs, to double your feature number you should quadrouble the number of data points to reduce the risk of overfitting. Thus there is a strong relationship between how complex your model can be, the achievable accuracy, the data required, and the noise in labels.

## 2.4. Bias Variance Decomposition¶

We will now try to be more systematic about this difference in model performance between training and testing data. Consider an unseen label $$y$$ and our model $$\hat{f}(\vec{x})$$. Our error on the unseen label is:

(2.4)$E\left[\left(y - \hat{f}(\vec{x})\right)^2\right]$

What is the expectation over? For now, let’s just assume the only source of randomness is in the noise from the label (recall $$y = f(\vec{x}) + \epsilon$$). Then our expression becomes:

(2.5)$$$E\left[\left(y - \hat{f}(\vec{x})\right)^2\right] = E\left[y^2\right] + E\left[\hat{f}(\vec{x})^2\right] - E\left[y\hat{f}(\vec{x})\right]$$$
(2.6)$$$E\left[\left(y - \hat{f}(\vec{x})\right)^2\right] = E\left[\left(f(\vec{x}) - \epsilon\right)^2\right] + \hat{f}(\vec{x})^2 - E\left[\left(f(\vec{x}) - \epsilon\right)\right]\hat{f}(\vec{x})$$$

I have dropped the expectations over deterministic expression $$\hat{f}$$. You can continue this, again dropping any $$E[f(\vec{x})]$$ terms and using the definition of $$\epsilon$$, a zero mean normal distribution with standard deviation $$\sigma$$. You will arrive at:

(2.7)$E\left[\left(y - \hat{f}(\vec{x})\right)^2\right] = \left(f(\vec{x}) - \hat{f}(\vec{x})\right)^2 + \sigma^2$

This expression means the best we can do on an unseen label is the noise of the label. This is very reasonable, and probably matches your intuition. The best you can do is match exactly the noise in the label when you have a perfect agreement between $$f(\vec{x})$$ and $$\hat{f}(\vec{x})$$

However, this analysis did not account for the fact our choice of training data is random. Things become more complex when we consider that our choice of training data is random. Return to Equation (2.4) and now replace $$\hat{f}\left(\vec{x}\right)$$ with $$\hat{f}\left(\vec{x}; \mathbf{D}\right)$$ where $$\mathbf{D}$$ is a random variable indicating the random data sample. You can find a complete derivation on Wikipedia. The key change is that $$\left(f(\vec{x}) - \hat{f}\left(\vec{x}; \mathbf{D}\right)\right)^2$$ is now a random variable. Equation (2.7) becomes:

(2.8)$E\left[\left(y - \hat{f}(\vec{x})\right)^2\right] = E\left[f(\vec{x}) - \hat{f}\left(\vec{x}; \mathbf{D}\right)\right]^2 + E\left[\left(E\left[\hat{f}\left(\vec{x}; \mathbf{D}\right)\right] - \hat{f}\left(\vec{x}; \mathbf{D}\right)\right)^2\right] + \sigma^2$

This expression is the most important equation for understanding ML and deep learning training. The first term in this expression is called bias and captures how far away our model is from the correct function $$f(\vec{x})$$. This is the expected (average) loss we get given a random dataset evaluated on a new unseen data point. You may think this the most important quantity – expected difference between the true function and our model on a new data point. However, bias does not determine the expected error on an unseen data point alone, there other terms.

The second term is surprising. It is called the variance and captures how much change at the unseen data point $$(\vec{x},y)$$ there is due to changes in the random variable $$\mathbf{D}$$. What is suprising is that the expected loss depends on the variance of the learned model. Think carefully about this. A model which is highly sensitive to which training data is chosen has a high expected error on test data. Furthermore, remember that this term variance is different than variance in a feature. It captures how the model value changes at a paritcular $$\vec{x}$$ as a function of changing the training data.

Note

There are three sources of randomness in the expectation: the choice of test data, the label noise, and the choice of training data. However, once you pick the training data, the test data is fixed so we do not indicate or worry about this. A quantity like $$E[\hat{f}(\vec{x})]$$ means splitting your data every possible way, fitting the models, then computing the value $$\hat{f}(\vec{x})$$ on the unseen test $$\vec{x}$$. Then you take the average over the unseen test values. You can also skip the last step and leave $$E[\hat{f}(\vec{x})]$$ as a function of $$\vec{x}$$, which is what is plotted in Fig. 2.3 and Fig. 2.4.

Fig. 2.3 A single feature fit to the polynomial model example above. The left panel shows a single train/test split and the resulting model fit. The right panel shows the result of many fits. The model variance is the variacne across each of those model fits and the bias is the agreement of the average model. It can be seen that this model has low variance but poor average agreement (high bias).

These three terms: noise, bias, and variance set the minimum value for test error. Noise is set by your data and not controlloble. However, bias and variance are controllable. What does a high bias, low variance model look like? A 1D linear model is a good example. See Fig. 2.3. It has one parameter so a sample of data points gives a conisistent estimate. However, a 1D model cannot capture the true $$f(\vec{x})$$ so it has a large average error (bias) at a given point. What does a low bias, high variance model look like? An overfit model like the one shown in Fig. 2.4. It has extreme outliers on test data, but on average it actually has a low bias.

Fig. 2.4 A 7 feature fit to the polynomial model example above. The left panel shows a single train/test split and the resulting model fit. The right panel shows the result of many fits. The model variance is the variance across each of those model fits and the bias is the agreement of the average model. It can be seen that this model has high variance but good average agreement (low bias).

Fig. 2.5 The bias, variance, and fit on test values for the polynomial example avearged across 2,500 train/test splits. As the number of features incerases, variance increases and bias decreases. There is a minum at 4 features. The plot stops at 5 because the variance becomes very large beyond 5.

The way to change bias and variance is through model complexity, which is feature number in our linear models. Increasing model complexity reduces bias and increases variance. There is an optimum for our polynomial example, shown in Fig. 2.5. Indeed this is true of most ML models, although it can be difficult to cleanly increase model complexity and keep training converged. However, this is not typically true in deep learning with neural networks[NMB+18].

Note

The bias–variance tradeoff for model complexity is based on experience. The decomposition above does not imply it. Intentionally underfitting, adding noise, and exchanging one feature for another are all ways to affect bias and variance without adjusting complexity. Also, sometimes you can just improve both with better models.

The bias–variance tradeoff is powerful for explaining the intuition we’ve learned from examples above. Large datasets reduce model variance, explaining why it is possible to increase model complexity to improve model accuracy only with larger datasets. Overfitting reduces bias at the cost of high variance. Not training long enough increases bias, but reduces variance as well since you can only move so far from your starting parameters.

## 2.5. Regularization¶

Adding featuers is a challenging way to exchange model bias and variance because it comes in discrete steps and some features are just better than others. A different way is to use a complex model (all features) but reduce variance through regularization. Regaulrization is the addition of an extra term to your loss function that captures some unwanted property about your model that you want to minimize.

### 2.5.1. L2¶

Our first example is the magnitude of fit coefficients. The magnitude of the coefficients is $$\sum_k w_k^2$$ where $$w_k$$ the index of a single coefficient. We add this to our loss function:

(2.9)$$$L = \frac{1}{N}\sum_i^N \left[y_i - \hat{f}(\vec{x}_i, \vec{w}, b)\right]^2 + \lambda \left(\sum_k w_k^2 + b^2\right)$$$

where $$\lambda$$ is our strength of regularization. By changing $$\lambda$$, we control how large the magnitude of our parameters are and that directly reduces the variance. You can see the result in Fig. 2.6 for our polynomial example. Increasing the strength of regularization decreases variance at the cost of increasing bias. Remember in deep learning there isn’t as much of a tradeoff and often you just get a reduction in variance with no degredation in bias. Adding L2 regularization with a linear model has a specific name: Ridge Regression.

Fig. 2.6 A 7 feature fit to the polynomial model example above with increasing strength of regularization. The vertical bars indicate standard deviation of model at each point.

Why does this work? Look at the gradient of a particular weight of our new loss function:

(2.10)$$$\frac{\partial L}{\partial w_4} = \frac{2}{N}\sum_i^N \left[y_i - \hat{f}(\vec{x}_i, \vec{w}, b)\right]\frac{\partial \hat{f}(\vec{x}_i, \vec{w}, b)}{\partial w_4} + 2\lambda w_4$$$

where $$w_4$$ is one of our weights. The first term on the right-hand side accounts for how $$w_4$$ affects our accuracy, like usual. The second term is from the regularization. You can see that the gradient is just the value of weight times a constant. Let’s contract the first term into a variable called $$g_{w_4}$$ and look at how this new gradient affects our updates to $$w_4$$. Our gradient descent update of $$w_4$$ becomes:

(2.11)$$$w_4' = w_4 -\eta g_{w_4} - 2\eta\lambda w_4$$$

So our regularization pushes $$w_4'$$ to always have a lower magnitude. If $$w_4' = 2.5$$, the update will include a term of $$-2\eta \lambda 2.5$$, pushing our weight value closer to zero. This means our weights always are pushed towards zero. Of course the term coming from model error ($$g_{w_4}$$) also has an effect so that we end up at a balance of lower magnitude weights and model error. We control that balance through the $$\lambda$$ term.

### 2.5.2. L1¶

L1 regularization changes our loss to be the following:

(2.12)$$$L = \frac{1}{N}\sum_i^N \left[y_i - \hat{f}(\vec{x}_i, \vec{w}, b)\right]^2 + \lambda \left(\sum_k \left|w_k\right| + \left|b\right|\right)$$$

It may appear at first that this is identical to L2. In fact, the L1 regularization has a powerful benefit: it induces sparsity. L2 just causes regression coefficients to be on average lower, but L1 forces some coefficients to be 0. This gives us a kind of “automatic” feature selection. This is called Lasso Regression when you combine L1 regularization with linear regression. In general, L2 gives a better model and L1 gives a more interpretable result by zeroing features. This is an overgeneralization but a good starting guess.

## 2.6. Strategies to Assess Models¶

We will now discuss more ways to assess model performance. These are more robust approaches to assess loss on testing data.

### 2.6.1. k-Fold Cross-Validation¶

The bias–variance decomposition shows that our testing error is sensitive to what training data has been chosen. The expected mean test error $$E\left[\left(y - \hat{f}(\vec{x})\right)^2\right]$$ depends on the label noise and the way we split our data into training and testing data. Thus far, we’ve only gotten a single sample from this expectation by splitting. One way to better estimate the value on unseen data is to repeat the process of splitting data into training and testing multiple times. This is called k-fold cross-validation, where $$k$$ is the number of times you repeat the process. k-fold cross-validation is useful because certain high-variance model choices can give different testing errors depending on the train/test split. k-fold also provides multiple samples so that you can estimate the uncertainty in testing error. As all things to do with model variance, the smaller the dataset the more important this is. Typically with very large datasets k-fold crosss validation is not done because label noise dominates and testing a model k times can be time-consuming.

k-fold cross-validation has a specific process for splitting testing and training data. What we did previously was split into a 50/50 split of training and testing. In k-fold, we split our data into k segments. Then we train on k-1 segments and test on the last segment. You can do this k-ways. For example, with K = 3 you would split your data into A, B, C. The first train/test split would be A, B for training and C for testing. Then B, C for training and A for testing. The last would be A, C for training and B for testing. Following this procedure means that your percentage split will be 90/10 for $$k = 10$$ and 50/50 for $$k = 2$$. This has a disadvantage that the number of estimates for testing error depends on size of train/test split. For example, you cannot get 10 estimates for an 80/20 split. An 80/20 split means exactly 5-fold cross-validation. We’ll see other methods that relax this later on.

Let’s now use k-fold cross in two examples: our full dataset and a smaller 25 data point sample. Rather than use gradient descent here, we’ll just use the pseudo-inverse to keep our code simple.

k = 10
N = len(soldata)
# make indices for the k segments
splits = list(range(0, N + N // k, N // k))
error = []
for i in range(k):
# slice out segments
test = soldata[splits[i]:splits[i + 1]]
test_x, test_y = test[feature_names].values, test['Solubility'].values
train = pd.concat([soldata[splits[i]:],soldata[:splits[i + 1]]])
x, y = train[feature_names].values, train['Solubility'].values
# compute coefficients
w, *_ = np.linalg.lstsq(x, y)
# compute intercept (b)
b = np.mean(y - np.dot(x, w))
# compute test erropr
error.append(np.mean((np.dot(test_x, w) + b - test_y)**2))
plt.plot(error, 'o')
plt.xlabel('Split Number')
plt.ylabel('Test Error')
plt.title(f'{k}-fold cross-validation of soldata')
plt.show()


The final answer in this case is the average of these values: 2.63$$\pm$$1.77. The advantage of the k-fold is that we can report standard deviation like this.

Now what effect does k have on this process? Let’s see how our choice of k matters

N = len(soldata)
error = []
error_std = []
for k in range(2, 25):
splits = list(range(0, N + N // k, N // k))
k_error = []
for i in range(k):
# slice out segments
test = soldata[splits[i]:splits[i + 1]]
test_x, test_y = test[feature_names].values, test['Solubility'].values
train = pd.concat([soldata[splits[i]:],soldata[:splits[i + 1]]])
x, y = train[feature_names].values, train['Solubility'].values
# compute coefficients
w, *_ = np.linalg.lstsq(x, y)
# compute intercept (b)
b = np.mean(y - np.dot(x, w))
# compute test erropr
k_error.append(np.mean((np.dot(test_x, w) + b - test_y)**2))
error.append(np.mean(k_error))
error_std.append(np.std(k_error,ddof=1))
plt.errorbar(range(2, 25), error, yerr=error_std, capsize=6)
plt.xlabel('k')
plt.ylabel('Test Error')
plt.title('k-fold cross-validation of soldata')
plt.show()


As you can see, there is not much sensitivity to k. This is good, because k is mostly arbitrary. Larger k means more samples, but each test data is smaller so that these two effects should balance out.

Large datasets are not that sensitive because the training and testing splits are large. Let us know examine what happens with $$N = 25$$, a common case in chemistry data. We’ll just pick 25 data points at the beginning and not change that choice, mocking what would happen in a real example.

small_soldata = soldata.sample(25, replace=False)
N = len(small_soldata)
error = []
error_std = []
for k in range(2, 25):
splits = list(range(0, N + N // k, N // k))
k_error = []
for i in range(k):
# slice out segments
test = small_soldata[splits[i]:splits[i + 1]]
test_x, test_y = test[feature_names].values, test['Solubility'].values
train = pd.concat([small_soldata[splits[i]:],small_soldata[:splits[i + 1]]])
x, y = train[feature_names].values, train['Solubility'].values
# compute coefficients
w, *_ = np.linalg.lstsq(x, y)
# compute intercept (b)
b = np.mean(y - np.dot(x, w))
# compute test erropr
k_error.append(np.mean((np.dot(test_x, w) + b - test_y)**2))
error.append(np.mean(k_error))
error_std.append(np.std(k_error,ddof=1))
plt.errorbar(range(2, 25), error, yerr=error_std, capsize=6)
plt.xlabel('k')
plt.ylabel('Test Error')
plt.title('k-fold cross-validation of soldata subsample')
plt.show()


Our results are a little sensitive to the choice of $$k$$. Now why might test error decrease? Remember that a larger $$k$$ means more data points for training. This did not matter above when we had 10,000 data points. Now it is very importatnt, since we only have 25 data points. Thus larger k means more training data.

### 2.6.2. Leave-one-out CV¶

Larger k means more training data, so what is the largest it can be? Remember that k is the number segments in your data. So $$k = N$$ is the max, where each data point is a segement. This is called leave-one-out cross-validation (LOOCV). It creates $$N$$ different models, one for each data point left out, and so is only used for small datasets. Thus the advantage of LOOCV is it maximizes training data, but maximizes the number of models needing to be trained.

## 2.7. Computing Other Measures¶

Using LOOCV and k-fold cross-validation, we’re able to predict test error. This “test error” is specifically an expected error on an unseen data point. Now how do we actually treat a new data point? What will we report as the certainty in a new point? The test error? We’ll call this point the prediction point and we’ll try to estimate the quantiles of this point. Quantiles are the building blocks for confidence intervals. Recall that confidence intervals allow us to report our model prediction as $$4.3 \pm 0.2$$, for example.

### 2.7.1. Bootstrap Resampling¶

To estimate quantiles, we need to have a series of obervation of predictions from the prediction point $$\hat{f}(\vec{x}')$$, where $$\vec{x}'$$ is the prediction point. For example, we could do 5-fold cross-validation and have 5 estimates of $$\hat{f}_k(\vec{x}')$$ and could estimate the quantiles using a t-statistic. Instead, we’ll use a method called bootstrap resampling which removes the restriction that we can only use $$1 - 1 / k$$ of the training data. Bootstrap resampling is a general process for estimating uncertainty for empricial statistics without assuming a probability distribution (i.e., non-parametric). In bootstrap resampling, we create as many as desired new training datasets that are the same size as the original by sampling with replacement from the original dataset. That means our new dataset has less members than the original and makes-up the difference with duplicates. Let’s see an example. If your training dataset originally has data A, B, C, D, E, our bootstrap resampled training data is:

1. A, B, B, D, E

2. B, C, C, C, E

3. A, B, D, E, E

4. A, B, C, D, E

5. A, A, C, C, D

and so forth. The “with replacement” means that we allow repeats. This gives some variation to our training data. It also means we can generate $$2^N$$ new datasets, which is practically as many as we want. Let’s see now how we could use this to quantile the estimate for a prediction on a test point. We’ll set $$N = 1000$$ and do bootstrap resampling for 100 iterations.

# Create training data and 1 test point
N = 1000
# this line gets the data for our example
# it is not the bootstrap resampling
tmp = soldata.sample(N + 1, replace=False)
small_soldata = tmp.iloc[:N]
predict_point = tmp.iloc[-1]

samples = 100
predictions = []
for i in range(N):
#choose with replacement indices to make new dataset
idx = np.random.choice(np.arange(N), size=N, replace=True)
train = small_soldata.iloc[idx]
x, y = train[feature_names].values, train['Solubility'].values
# compute coefficients
w, *_ = np.linalg.lstsq(x, y)
# compute intercept (b)
b = np.mean(y - np.dot(x, w))
# compute test prediction
predictions.append(np.dot(predict_point[feature_names].values, w) + b)
# compute quantiles (lower, median, upper)
qint = np.quantile(predictions, [0.025, 0.5, 0.975])
# compute avg distance from medianto report +/-
print(f'prediction = {qint[1]:.2f} +/- {(qint[-1] - qint[0]) / 2:.2f}, label = {predict_point["Solubility"]:.2f}')

prediction = -3.77 +/- 0.61, label = -3.45


The resulting prediction has confidence intervals, thanks to the bootstrap resampling. This approach has a few disadvantages though. The first is that we need to produce and keep 100 models, one for each bootstrap resample. Of course you could choose a fewer number, but you need to have enough for good statistics. Another issue is that this process does not give a reportable test error. We could further split our data again and do k-fold cross-validation on this approach to get test error. However, this is bit overcomplex and then we’ll be at a similar problem that we’ll have k sets of 100 models and it’s not obvious how to combine them. It also under-estimates the error, because it has no estimate of the test error. It only accounts for variation due to training data. Using the language above, it only accounts for model variance but not model bias.

Bootstrap resampling is still an excellent technique that is used often to estimate uncertainties. However, it is not a great choice for estimating model error on unseen datapoints.

### 2.7.2. Jacknife+¶

An alternative approach that accounts for model variance like the bootstrap method and model bias like the k-fold cross-validation method is called Jacknife+ [BCRT19]. Jacknife+ carriers strong guarantees about accuracy of the confidence intervals generated, regardless of the underlying data or model. The change now is that we use LOOCV to create an ensemble of models (although you can subsample down if you do not want N of them) and also compute the models’ test error on the withheld test data. The final quantile estimates incorporate the variance from the variety of models (model variance) and also each models’ individual test error (model bias). Specifically, we compute:

(2.13)$$$R_i = \left|y_i - \hat{f}(\vec{x}_i;\,\mathbf{X} \setminus \vec{x}_i )\right|$$$

where $$\mathbf{X} \setminus \vec{x}_i$$ is the dataset to train the $$i$$th model and is the dataset excluding point $$(\vec{x}_i, y_i)$$, $$\hat{f}(\vec{x}_i;\,\mathbf{X} \setminus \vec{x}_i )$$ is the $$i$$th model evaluated on point $$\vec{x}_i$$, and $$R_i$$ is the residual of model $$i$$ computed by taking the difference between the label and prediction on point $$i$$. $$R_i$$ encodes how good the $$i$$th model is. We then combine it with the predictions on our new test point $$(\vec{x}', y')$$ to make our set for quantiling

(2.14)$$$q_1 = \left\{\hat{f}(\vec{x}_i;\,\mathbf{X} \setminus \vec{x}_i ) - R_i\right\}$$$
(2.15)$$$q_2 = \left\{\hat{f}(\vec{x}_i;\,\mathbf{X} \setminus \vec{x}_i ) + R_i\right\}$$$

The first set, with $$- R_i$$, is how low below the estimate from the $$i$$th model we could expect to see our prediction based on how the $$i$$th model did on its test point. The second set, with $$+ R_i$$, is how high below the estimate from the $$i$$th model we could expect to see our prediction based on how the $$i$$th model did on its test point. To compute our final value, we take the median of $$\hat{f}(\vec{x}_i;\,\mathbf{X} \setminus \vec{x}_i )$$ and report the lower end of the interval as the 5% quantile of $$q_1$$ and the top as the 95% quantile of $$q_2$$. You can see that this method combines the ensemble of prediction models given by bootstrap resampling with the error esimtates from LOOCV. Let’s see an example.

residuals = []
predictions = []
for i in range(N):
# make train excluding test point
# we just make a set and remove one element from it
# and then convert back to list
idx = list(set(range(N)) - set([i]))
train = small_soldata.iloc[idx]
x, y = train[feature_names].values, train['Solubility'].values
# compute coefficients
w, *_ = np.linalg.lstsq(x, y)
# compute intercept (b)
b = np.mean(y - np.dot(x, w))
# compute test prediction
predictions.append(np.dot(predict_point[feature_names].values, w) + b)
# now compute residual on withtheld point
yhat = np.dot(small_soldata.iloc[idx][feature_names].values, w) + b
residuals.append(np.abs(yhat - small_soldata.iloc[idx]['Solubility']))
# create our set of prediction - R_i and prediction + R_i
q1 = [p - ri for p,ri in zip(predictions, residuals)]
q2 = [p + ri for p,ri in zip(predictions, residuals)]
# compute quantiles (lower, median, upper)
qlow = np.quantile(q1, [0.05])[0]
qhigh = np.quantile(q2, [0.95])[0]
# compute avg distance from medianto report +/-
print(f'prediction = {np.median(predictions):.2f} +/- {(qlow - qhigh) / 2:.2f}, label = {predict_point["Solubility"]:.2f}')
print(f'Average test error = {np.median(residuals):.2f}')

prediction = -3.91 +/- -3.19, label = -3.45
Average test error = 1.07


The uncertainty is much higher! You can see that the residuals add about 1 solubility unit and the variability in the data adds about 2 solubility unit. Jacknife+ should be the preferred method when you have small datasets (1-1000) and can train models quickly enough to be able to compute 1000 of them. You can also replace the exhaustive LOOCV with a random process, where you only do a few iterations (like 25) of LOOCV to avoid computing so many models.

## 2.8. Training Data Distribution¶

We have come a long ways now. We’re able to compute test error, identify overfitting, understand model bias and variance, and predict uncertainty on unseen data points. One of the implied assumptions so far is that our splitting of data into training and testing data mimics what it will be like to predict on an unseen data point. More specifically, we assume that testing data comes from the same probability distribution as our training data. This is true when we’re doing the splitting, but is often violated when we actually get new data to make predictions with.

There are specific categoriers for how we have left the training distribution. Covariate shift is when the distribution of features changes. Covariate is another word for features. An example might be that the molecular weights of your molecules are larger in your testing data. The relationship between features and labels, $$f(\vec{x})$$ remains the same, but the distribution of features is different. Label shift means that we have the distribution of labels has changed. Perhaps our training data was all very soluble molecules but at test time, we’re examining mostly insoluble molecules. Again, our fundamental relationship $$f(\vec{x})$$ that we try to estimate with our model still holds.

There are two common reasons unseen data can be out of the training data distribution. The first is that you are extrapolating to new regions of chemical space. For example, you have training data of drug activities. You make a model that can predict activity. What do you do with the model? You obviously find the highest activity drug molecule. However, this molecule is likely to be unusual and not in your training data. If it was in your training data you would probably already be done – namely, you already synthesized and found a molecule with very high activity. Thus you will be pushing your model to regions outside of your training data. Another reason you can be out of training data is that the way you generated training data is different than how the model is used. For example, perhaps you trained on molecules that do not contain fluorine. Then you try your model on molecules that contain fluorine. Your features will be different than what you observed in training. The result of leaving your traning data distribution is that your test error increases and the estimates you provide will be too low.

### 2.8.1. Leave one class out cross-validation¶

Thus understanding and assessing training data distribution is an important task. In general, standard models that minimize a loss are poor at predicting extreme values. We will approach this challenge later with specific methods like black-box function optimization. For now, be wary of using your models as tools to find extreme values. The second challenge, that you’re leaving your training data due to how points are generated, can be assessed by computing a more realistic estimate of model error. This leads us to leave one class out cross-validation (LOCOCV).

In LOCOCV, we must first assign a class to each training data point. This is domain specific. It could be based on the molecule. You could use a clustering method. In our case, our solubility data actually is a combination of five other datasets so our data is already pre-classified based on who measured the solubility. We will now perform a kind of k-fold cross-validation, leaving one class out at a time and asssessing model error. We’ll compare this to k-fold cross-validation without classes.

# let's see what the groups (classes) are
unique_classes = soldata['Group'].unique()
print(unique_classes)

['G1' 'G3' 'G5' 'G4' 'G2']

# Leave one class out CV
N = len(soldata)
error = []
error_std = []
for c in unique_classes:
# slice out segments
test = soldata.loc[soldata['Group'] == c]
train = soldata.loc[soldata['Group'] != c]
test_x, test_y = test[feature_names].values, test['Solubility'].values
x, y = train[feature_names].values, train['Solubility'].values
# compute coefficients
w, *_ = np.linalg.lstsq(x, y)
# compute intercept (b)
b = np.mean(y - np.dot(x, w))
# compute test erropr
k_error.append(np.mean((np.dot(test_x, w) + b - test_y)**2))
error.append(np.mean(k_error))
error_std.append(np.std(k_error,ddof=1))
print(f'test error = {np.mean(error):.2f}')

test error = 0.97


We computed above what the 5-fold cross-validation is for this data, 2.67. You can see the LOCOCV test error (0.97) is similar, which means our different data sources agree well. So perhaps on new unseen data we can expect similar (not so great) accuracy. There may be other ways to group this data into classes, like based on molecular weight or which atoms are contained in the molecule. It depends on what you believe to be important. Breaking it down into the constituent datasets, like we did above, is a reasonable approach because it captures how different research groups would measure solubility. It is not always obvious or possible to use LOCOCV, but it should be something you consider to assess out of training data distribution. You can read more about the issue of leaving training data distribution for materials in this recent article [SBG+20].

## 2.9. Chapter Summary¶

• Regression is supervised learning where the labels are real numbers. We only considered scalars

• To assess a regressed model, we split data into training and testing and only report error on testing data

• Overfitting causes a mismatch between training and testing error

• Overfitting can be understood via the bias-variance decomposition

• Increasing model complexity can improve fit (reduce bias), but increases model variance and thus test error

• Regularization is a strategy to decrease model variance. L2 is a good first choice

• More rigorous assessment of models can be done via k-fold cross-validation or Jacknife+ when the training data is small enough that we can train multiple models

• Much of our model assessments depends on the testing data being from the same distribution as the training data (similar values). This is often not true and can be measured with leave-one-class-out cross-validation.

## 2.10. Exercises¶

### 2.10.1. Overfitting¶

1. What happens if we have redundant features but no noise? Is it possible to overfit?

2. We said that increasing dataset size reduces model variance. Show this by using k-fold cross validation on a few different dataset sizes.

### 2.10.2. Regularization¶

1. Implement L1 regularization on the solubility data with $$N = 35$$ data points. Increase the strength until some features go to zero. Which ones are they? Why do you think they go to zero first?

2. Repeat 1 with a few different sets of training data. Are your results consistent on which features disappear? Based on your results, do you think there is meaning to the features which go to zero?

3. Implement the L-infinity (supremum norm) regularization, which returns the absolute value of the maximum element only.

### 2.10.3. Model Assessment¶

1. Develop the best liear model for the complete solubility dataset and assess using your best judgement. Justify your choice of model and assessment.

## 2.11. Cited References¶

Alp20

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Bal19

Prasanna V Balachandran. Machine learning guided design of functional materials with targeted properties. Computational Materials Science, 164:82–90, 2019.

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Rina Foygel Barber, Emmanuel J Candes, Aaditya Ramdas, and Ryan J Tibshirani. Predictive inference with the jackknife+. arXiv preprint arXiv:1905.02928, 2019.

BJW18

Rainier Barrett, Shaoyi Jiang, and Andrew D White. Classifying antimicrobial and multifunctional peptides with bayesian network models. Peptide Science, 110(4):e24079, 2018.

Bis06

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CBHK02

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Rafael Gómez-Bombarelli and Alán Aspuru-Guzik. Machine learning and big-data in computational chemistry. Handbook of Materials Modeling: Methods: Theory and Modeling, pages 1939–1962, 2020.

MTKT18

Hirotomo Moriwaki, Yu-Shi Tian, Norihito Kawashita, and Tatsuya Takagi. Mordred: a molecular descriptor calculator. Journal of cheminformatics, 10(1):4, 2018.

NDJ+18

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NMB+18

Brady Neal, Sarthak Mittal, Aristide Baratin, Vinayak Tantia, Matthew Scicluna, Simon Lacoste-Julien, and Ioannis Mitliagkas. A modern take on the bias-variance tradeoff in neural networks. arXiv preprint arXiv:1810.08591, 2018.

RTMullerVL12

Matthias Rupp, Alexandre Tkatchenko, Klaus-Robert Müller, and O Anatole Von Lilienfeld. Fast and accurate modeling of molecular atomization energies with machine learning. Physical review letters, 108(5):058301, 2012.

SSAB20

Christoph Scherer, René Scheid, Denis Andrienko, and Tristan Bereau. Kernel-based machine learning for efficient simulations of molecular liquids. Journal of Chemical Theory and Computation, 16(5):3194–3204, 2020.

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Murat Cihan Sorkun, Abhishek Khetan, and Süleyman Er. AqSolDB, a curated reference set of aqueous solubility and 2D descriptors for a diverse set of compounds. Sci. Data, 6(1):143, 2019. doi:10.1038/s41597-019-0151-1.

SZY+19

Wenbo Sun, Yujie Zheng, Ke Yang, Qi Zhang, Akeel A Shah, Zhou Wu, Yuyang Sun, Liang Feng, Dongyang Chen, Zeyun Xiao, and others. Machine learning–assisted molecular design and efficiency prediction for high-performance organic photovoltaic materials. Science advances, 5(11):eaay4275, 2019.

SBG+20

Christopher Sutton, Mario Boley, Luca M Ghiringhelli, Matthias Rupp, Jilles Vreeken, and Matthias Scheffler. Identifying domains of applicability of machine learning models for materials science. Nature Communications, 11(1):1–9, 2020.

WRF+18

Zhenqin Wu, Bharath Ramsundar, Evan N Feinberg, Joseph Gomes, Caleb Geniesse, Aneesh S Pappu, Karl Leswing, and Vijay Pande. Moleculenet: a benchmark for molecular machine learning. Chemical science, 9(2):513–530, 2018.

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Tian Xie, Arthur France-Lanord, Yanming Wang, Yang Shao-Horn, and Jeffrey C Grossman. Graph dynamical networks for unsupervised learning of atomic scale dynamics in materials. Nature communications, 10(1):1–9, 2019.